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HIbernate--HQL举例+详解(三)
阅读量:2443 次
发布时间:2019-05-10

本文共 12809 字,大约阅读时间需要 42 分钟。

多表查询

准备数据

增加一个LinkMAN实体类,与Customer形成多对一关系。

public class Customer {
private Long cust_id; private String cust_name; private String cust_source; private String cust_industry; private String cust_level; private String cust_linkman; private String cust_phone; private String cust_mobile; //使用set集合,表达一对多关系 private Set
linkMens = new HashSet
(); public Customer() {
} public Set
getLinkMens() {
return linkMens; } public void setLinkMens(Set
linkMens) {
this.linkMens = linkMens; } public Long getCust_id() {
return cust_id; } public void setCust_id(Long cust_id) {
this.cust_id = cust_id; } public String getCust_name() {
return cust_name; } public void setCust_name(String cust_name) {
this.cust_name = cust_name; } public String getCust_source() {
return cust_source; } public void setCust_source(String cust_source) {
this.cust_source = cust_source; } public String getCust_industry() {
return cust_industry; } public void setCust_industry(String cust_industry) {
this.cust_industry = cust_industry; } public String getCust_level() {
return cust_level; } public void setCust_level(String cust_level) {
this.cust_level = cust_level; } public String getCust_linkman() {
return cust_linkman; } public void setCust_linkman(String cust_linkman) {
this.cust_linkman = cust_linkman; } public String getCust_phone() {
return cust_phone; } public void setCust_phone(String cust_phone) {
this.cust_phone = cust_phone; } public String getCust_mobile() {
return cust_mobile; } public void setCust_mobile(String cust_mobile) {
this.cust_mobile = cust_mobile; } public Customer(Long cust_id, String cust_name, String cust_level) {
super(); this.cust_id = cust_id; this.cust_name = cust_name; this.cust_level = cust_level; }}
public class LinkMan {
private Long lkm_id; private Character lkm_gender; private String lkm_name; private String lkm_phone; private String lkm_email; private String lkm_qq; private String lkm_mobile; private String lkm_memo; private String lkm_position; //表达多对一关系 private Customer customer ; public Customer getCustomer() {
return customer; } public void setCustomer(Customer customer) {
this.customer = customer; } public Long getLkm_id() {
return lkm_id; } public void setLkm_id(Long lkm_id) {
this.lkm_id = lkm_id; } public Character getLkm_gender() {
return lkm_gender; } public void setLkm_gender(Character lkm_gender) {
this.lkm_gender = lkm_gender; } public String getLkm_name() {
return lkm_name; } public void setLkm_name(String lkm_name) {
this.lkm_name = lkm_name; } public String getLkm_phone() {
return lkm_phone; } public void setLkm_phone(String lkm_phone) {
this.lkm_phone = lkm_phone; } public String getLkm_email() {
return lkm_email; } public void setLkm_email(String lkm_email) {
this.lkm_email = lkm_email; } public String getLkm_qq() {
return lkm_qq; } public void setLkm_qq(String lkm_qq) {
this.lkm_qq = lkm_qq; } public String getLkm_mobile() {
return lkm_mobile; } public void setLkm_mobile(String lkm_mobile) {
this.lkm_mobile = lkm_mobile; } public String getLkm_memo() {
return lkm_memo; } public void setLkm_memo(String lkm_memo) {
this.lkm_memo = lkm_memo; } public String getLkm_position() {
return lkm_position; } public void setLkm_position(String lkm_position) {
this.lkm_position = lkm_position; }}

表中数据如下:

在这里插入图片描述
在这里插入图片描述

内连接和迫切内连接

  • 内连接
    SQL语句:select * from cst_customer cus,cst_linkman lin where cus.cust_id=lin.lkm_cust_id
    hql语句:from Customer c inner join c.linkMens
    query.list()返回的list里面每部分是数组形式
  • 迫切内连接
    迫切内连接和内连接底层实现一样
    区别:使用内连接返回list每部分是数组,使用迫切内连接返回list每部分是对象。
    hql语句:from Customer c inner join fetch c.linkMens

例子:

//内连接和迫切内连接@Test	public void fun1(){
Session session = HibernateUtils.openSession(); Transaction tx = session.beginTransaction(); //---------------------------------------------------- String hql1 = " from Customer c inner join c.linkMens ";//内连接 String hql2 = "from Customer c inner join fetch c.linkMens";//迫切内连接 Query query1 = session.createQuery(hql1); Query query2 = session.createQuery(hql2); List
list1 = query1.list(); List
list2 = query2.list(); for(Object[] arr : list1){
System.out.println(Arrays.toString(arr)); } System.out.println(list2); //---------------------------------------------------- tx.commit(); session.close(); }

运行JUnit测试输出:

Hibernate:     select        customer0_.cust_id as cust_id1_0_0_,        linkmens1_.lkm_id as lkm_id1_1_1_,        customer0_.cust_name as cust_nam2_0_0_,        customer0_.cust_source as cust_sou3_0_0_,        customer0_.cust_industry as cust_ind4_0_0_,        customer0_.cust_level as cust_lev5_0_0_,        customer0_.cust_linkman as cust_lin6_0_0_,        customer0_.cust_phone as cust_pho7_0_0_,        customer0_.cust_mobile as cust_mob8_0_0_,        linkmens1_.lkm_gender as lkm_gend2_1_1_,        linkmens1_.lkm_name as lkm_name3_1_1_,        linkmens1_.lkm_phone as lkm_phon4_1_1_,        linkmens1_.lkm_email as lkm_emai5_1_1_,        linkmens1_.lkm_qq as lkm_qq6_1_1_,        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,        linkmens1_.lkm_memo as lkm_memo8_1_1_,        linkmens1_.lkm_position as lkm_posi9_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_1_     from        cst_customer customer0_     inner join        cst_linkman linkmens1_             on customer0_.cust_id=linkmens1_.lkm_cust_idHibernate:     select        customer0_.cust_id as cust_id1_0_0_,        linkmens1_.lkm_id as lkm_id1_1_1_,        customer0_.cust_name as cust_nam2_0_0_,        customer0_.cust_source as cust_sou3_0_0_,        customer0_.cust_industry as cust_ind4_0_0_,        customer0_.cust_level as cust_lev5_0_0_,        customer0_.cust_linkman as cust_lin6_0_0_,        customer0_.cust_phone as cust_pho7_0_0_,        customer0_.cust_mobile as cust_mob8_0_0_,        linkmens1_.lkm_gender as lkm_gend2_1_1_,        linkmens1_.lkm_name as lkm_name3_1_1_,        linkmens1_.lkm_phone as lkm_phon4_1_1_,        linkmens1_.lkm_email as lkm_emai5_1_1_,        linkmens1_.lkm_qq as lkm_qq6_1_1_,        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,        linkmens1_.lkm_memo as lkm_memo8_1_1_,        linkmens1_.lkm_position as lkm_posi9_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_0__,        linkmens1_.lkm_id as lkm_id1_1_0__     from        cst_customer customer0_     inner join        cst_linkman linkmens1_             on customer0_.cust_id=linkmens1_.lkm_cust_id//内连接,两部分,以数组形式返回[per.zhang.domain.Customer@48e64352, per.zhang.domain.LinkMan@200606de][per.zhang.domain.Customer@48e64352, per.zhang.domain.LinkMan@750fe12e][per.zhang.domain.Customer@f8908f6, per.zhang.domain.LinkMan@3e587920][per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.LinkMan@24f43aa3][per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.LinkMan@63fd4873][per.zhang.domain.Customer@1e11bc55, per.zhang.domain.LinkMan@7544a1e4][per.zhang.domain.Customer@1e11bc55, per.zhang.domain.LinkMan@70e0accd][per.zhang.domain.Customer@7957dc72, per.zhang.domain.LinkMan@6ab72419]//迫切内连接 以对象形式返回,linkMan封装到了Customer的Set集合中[per.zhang.domain.Customer@48e64352, per.zhang.domain.Customer@48e64352, per.zhang.domain.Customer@f8908f6, per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.Customer@1e11bc55, per.zhang.domain.Customer@1e11bc55, per.zhang.domain.Customer@7957dc72]

外连接和迫切外连接

@Test	//外连接和迫切外连接	public void fun2(){
Session session = HibernateUtils.openSession(); Transaction tx = session.beginTransaction(); //---------------------------------------------------- String hql1 = " from Customer c right join c.linkMens ";//右外连接 String hql2 = " from Customer c right join fetch c.linkMens ";//迫切右外连接 Query query1 = session.createQuery(hql1); Query query2 = session.createQuery(hql2); List
list1 = query1.list(); List
list2 = query2.list(); for(Object[] arr : list1){
System.out.println(Arrays.toString(arr)); } System.out.println(list2); //---------------------------------------------------- tx.commit(); session.close(); }

运行JUnit测试输出:

Hibernate:     select        customer0_.cust_id as cust_id1_0_0_,        linkmens1_.lkm_id as lkm_id1_1_1_,        customer0_.cust_name as cust_nam2_0_0_,        customer0_.cust_source as cust_sou3_0_0_,        customer0_.cust_industry as cust_ind4_0_0_,        customer0_.cust_level as cust_lev5_0_0_,        customer0_.cust_linkman as cust_lin6_0_0_,        customer0_.cust_phone as cust_pho7_0_0_,        customer0_.cust_mobile as cust_mob8_0_0_,        linkmens1_.lkm_gender as lkm_gend2_1_1_,        linkmens1_.lkm_name as lkm_name3_1_1_,        linkmens1_.lkm_phone as lkm_phon4_1_1_,        linkmens1_.lkm_email as lkm_emai5_1_1_,        linkmens1_.lkm_qq as lkm_qq6_1_1_,        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,        linkmens1_.lkm_memo as lkm_memo8_1_1_,        linkmens1_.lkm_position as lkm_posi9_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_1_     from        cst_customer customer0_     right outer join        cst_linkman linkmens1_             on customer0_.cust_id=linkmens1_.lkm_cust_idHibernate:     select        customer0_.cust_id as cust_id1_0_0_,        linkmens1_.lkm_id as lkm_id1_1_1_,        customer0_.cust_name as cust_nam2_0_0_,        customer0_.cust_source as cust_sou3_0_0_,        customer0_.cust_industry as cust_ind4_0_0_,        customer0_.cust_level as cust_lev5_0_0_,        customer0_.cust_linkman as cust_lin6_0_0_,        customer0_.cust_phone as cust_pho7_0_0_,        customer0_.cust_mobile as cust_mob8_0_0_,        linkmens1_.lkm_gender as lkm_gend2_1_1_,        linkmens1_.lkm_name as lkm_name3_1_1_,        linkmens1_.lkm_phone as lkm_phon4_1_1_,        linkmens1_.lkm_email as lkm_emai5_1_1_,        linkmens1_.lkm_qq as lkm_qq6_1_1_,        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,        linkmens1_.lkm_memo as lkm_memo8_1_1_,        linkmens1_.lkm_position as lkm_posi9_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_1_,        linkmens1_.lkm_cust_id as lkm_cus10_1_0__,        linkmens1_.lkm_id as lkm_id1_1_0__     from        cst_customer customer0_     right outer join        cst_linkman linkmens1_             on customer0_.cust_id=linkmens1_.lkm_cust_id            //外连接,两部分,以数组形式返回[pers.zhang.domain.Customer@48e64352, pers.zhang.domain.LinkMan@200606de][pers.zhang.domain.Customer@48e64352, pers.zhang.domain.LinkMan@750fe12e][pers.zhang.domain.Customer@f8908f6, pers.zhang.domain.LinkMan@3e587920][pers.zhang.domain.Customer@2ef8a8c3, pers.zhang.domain.LinkMan@24f43aa3][pers.zhang.domain.Customer@2ef8a8c3, pers.zhang.domain.LinkMan@63fd4873][pers.zhang.domain.Customer@1e11bc55, pers.zhang.domain.LinkMan@7544a1e4][pers.zhang.domain.Customer@1e11bc55, pers.zhang.domain.LinkMan@70e0accd][pers.zhang.domain.Customer@7957dc72, pers.zhang.domain.LinkMan@6ab72419][null, pers.zhang.domain.LinkMan@3aacf32a]//外连接,以对象形式返回,linkMan封装到了Customer的Set集合中[cn.itcast.domain.Customer@48e64352, pers.zhang.domain.Customer@48e64352, cn.itcast.domain.Customer@f8908f6, pers.zhang.domain.Customer@2ef8a8c3, cn.itcast.domain.Customer@2ef8a8c3, pers.zhang.domain.Customer@1e11bc55, cn.itcast.domain.Customer@1e11bc55, pers.zhang.domain.Customer@7957dc72, null]

子查询

对于子查询的数据库,Hibernate支持在查询中使用子查询。一个子查询必须被圆括号包围起来(经常是SQL聚集函数的圆括号)。甚至相互关联的子查询(引用到外部查询中的别名的子查询)也是允许的。

select c.cust_id,c.cust_name,c.cust_level
from Customer c
where c.cust_id = (
select l.customer.cust_id
from LinkMan l
where l.lkm_name like ‘联想02’)

例子:

@Test	//子查询	public void fun4(){
Session session = HibernateUtils.openSession(); Transaction tx = session.beginTransaction(); //---------------------------------------------------- //查询linkman的名字为‘联想02’的customer对象的id,名字,和客户等级 String hql = "select c.cust_id,c.cust_name,c.cust_level " + "from Customer c " + "where c.cust_id = " + "(select l.customer.cust_id " + "from LinkMan l " + "where l.lkm_name like '联想02')"; Query query = session.createQuery(hql); List
list = query.list(); for(Object[] arr : list){
System.out.println(Arrays.toString(arr)); } //---------------------------------------------------- tx.commit(); session.close(); }

运行JUnit测试输出:

Hibernate:     select        customer0_.cust_id as col_0_0_,        customer0_.cust_name as col_1_0_,        customer0_.cust_level as col_2_0_     from        cst_customer customer0_     where        customer0_.cust_id=(            select                linkman1_.lkm_cust_id             from                cst_linkman linkman1_             where                linkman1_.lkm_name like '联想02'        )[2, 联想, 3]

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